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51
pyground/sugar/TestSugarRushSameSymbol.py
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51
pyground/sugar/TestSugarRushSameSymbol.py
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import unittest
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from SugarRush1000 import SugarRush1000
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def checkGrid(grid):
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total_scotter_count = 0
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for col in range(7):
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scotter_count = 0
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for row in range(7):
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if grid[row][col] == "S":
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scotter_count += 1
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total_scotter_count += 1
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if scotter_count > 1:
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print(f"col{col} has {scotter_count} scotter")
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return False
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if total_scotter_count > 7:
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print(f"total scotter count {total_scotter_count} > 7")
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return False
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return True
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class TestSugarRushLogic(unittest.TestCase):
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def test_same_symbol_clusters(self):
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mock_grid = [
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['A','E','E','A','B','A','F'],
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['E','E','E','B','C','D','E'],
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['E','E','S','C','A','A','A'],
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['A','B','A','D','E','B','B'],
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['B','E','E','A','E','E','A'],
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['E','C','D','E','B','E','B'],
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['A','F','E','A','A','E','A'],
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]
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game = SugarRush1000(balance=100000, bet=1, mock_grid=mock_grid)
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# 1. 触发
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import json
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result = game.doSpin()
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# print(json.dumps(result))
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assert len(result['steps'][0]['symbol_links']) == 2
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assert result['steps'][0]['symbol_links'][0]['symbol'] == 'E'
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assert result['steps'][0]['symbol_links'][1]['symbol'] == 'E'
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print("✅ 测试通过:同个符号多个cluster消除正常")
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if __name__ == "__main__":
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unittest.main(argv=["first-arg-is-ignored"], exit=False)
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